lib.sh: remove rmgit()

We don't need to call it from git.sh, because it's
only being done when building a release anyway,
and we already run rmgit when doing a release.

The function itself is only two simple fx_ calls,
so we can just do that from build_release().

Signed-off-by: Leah Rowe <leah@libreboot.org>

1 files changed, 0 insertions, 3 deletions

diff --git a/include/git.sh b/include/git.sh
index b65bd196..0091c832 100644
--- a/include/git.sh
+++ b/include/git.sh
@@ -57,9 +57,6 @@ git_prep()
 		dx_ fetch_submodule "$mdir/module.list"
 	fi
 
-	[ "$_loc" != "$XBMK_CACHE/repo/$project" ] && \
-	    [ "$XBMK_RELEASE" = "y" ] && rmgit "$tmpgit"
-
 	[ "$_loc" = "${_loc%/*}" ] || x_ mkdir -p "${_loc%/*}"
 	x_ mv "$tmpgit" "$_loc"
 }